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The microcurrent through the electrode in a dedicate circuit

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The microcurrent through the electrode in a dedicate circuit

by AAPL » Thu Nov 14, 2019 2:08 am
Magoosh

The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)

OA C
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by nitink » Thu Nov 14, 2019 3:27 am
Since the current has decreased by 1000 times. so the new current will be 1000 smaller than the original amount.

Original current = 3.8 * 10^-8

New current => 3.8 * 10^-8 /1000
= 3.8 * 10^-11

Answer C
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by Scott@TargetTestPrep » Mon Nov 18, 2019 8:31 am
AAPL wrote:Magoosh

The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)

OA C

3.6 x 10^(-8) x 1/1000

Noting that 1/1000 = 10^-3, we have:

= 3.6 x 10^(-8) x 10^(-3)

= 3.6 x 10^(-11)

Answer: C

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by Brent@GMATPrepNow » Mon Nov 18, 2019 8:49 am
AAPL wrote:Magoosh

The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)

OA C
Key concept #1: If X is 1000 times smaller than Y, we can write: X = Y/1000

Key concept #2: (ab)/c = (a)(b/c)

So, the measure of the resulting current = (3.6)[10^(−8)]/1000

Rewrite as: (3.6)[10^(−8)]/(10^3)

Use Concept #2 to rewrite as: (3.6)[10^(−8)/10^3]

Apply Quotient Law for exponents to get: (3.6)[10^(−8−3)]

Simplify: (3.6)[10^(−11)]

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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