BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

gmatprep - card game

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 659
Joined: Mon Dec 14, 2009 8:12 amFollowed by: 3 members
Thanked: 32 times
by Gurpinder » Mon Sep 20, 2010 8:16 am
from my understanding, the possible product is between 15 and 200, the game is to have 2 consecutive #'s that when multiplied give you values between 15 and 200

am i right?

4x5= 20 so the least # = 4.

but then 13*14=182. so shouldnt the largest # be 14?????
Attachments
card game.JPG
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 520
Joined: Mon Jun 14, 2010 10:44 amFollowed by: 6 members
Thanked: 70 times

by niksworth » Mon Sep 20, 2010 9:36 am
the child draws an integer from the deck and multiples it by the next integer (which might not necessarily be in the deck).

If the largest integer in the deck is 14, then the product, as given by the child, is 14*15 = 210.
Since the maximum possible product is 200, we cannot have 14 as the largest integer.

13 satisfies this, and so is the largest integer.
scio me nihil scire
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 422
Joined: Mon Aug 09, 2010 11:47 amFollowed by: 1 member
Thanked: 22 times
GMAT Score:680

by beatthegmatinsept » Mon Sep 20, 2010 9:41 am
Isnt the largest number in a 'deck of cards' always 13? So any answer choices with the range of numbers beyong 13 should be eliminated?
Being defeated is often only a temporary condition. Giving up is what makes it permanent.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2623
Joined: Mon Jun 02, 2008 3:17 amFollowed by: 355 members
Location: Montreal
Thanked: 1090 times
GMAT Score:780

by Ian Stewart » Mon Sep 20, 2010 9:52 am
Gurpinder wrote:from my understanding, the possible product is between 15 and 200, the game is to have 2 consecutive #'s that when multiplied give you values between 15 and 200

am i right?

4x5= 20 so the least # = 4.

but then 13*14=182. so shouldnt the largest # be 14?????
Yes, your understanding is correct, but bear in mind it's the smaller of the two consecutive numbers which appears on the card that is selected. So when we play this game, if we pick a '13' on our card, we will multiply 13*14 = 182. If we were to have a '14' among the cards, then when we picked '14' we'd calculate 14*15 = 210, which is too large. So 13 is the largest number that can appear on a card.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 520
Joined: Mon Jun 14, 2010 10:44 amFollowed by: 6 members
Thanked: 70 times

by niksworth » Mon Sep 20, 2010 10:02 am
beatthegmatinsept wrote:Isnt the largest number in a 'deck of cards' always 13? So any answer choices with the range of numbers beyong 13 should be eliminated?
I can't believe that you have used this logic to solve this problem :)

And, while a deck of cards has 13 cards in a single suite, no card is numbered or valued 13!!
scio me nihil scire
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 422
Joined: Mon Aug 09, 2010 11:47 amFollowed by: 1 member
Thanked: 22 times
GMAT Score:680

by beatthegmatinsept » Mon Sep 20, 2010 10:08 am
niksworth wrote:
beatthegmatinsept wrote:Isnt the largest number in a 'deck of cards' always 13? So any answer choices with the range of numbers beyong 13 should be eliminated?
I can't believe that you have used this logic to solve this problem :)

And, while a deck of cards has 13 cards in a single suite, no card is numbered or valued 13!!
LOL.. King stands for 13 ;)

No, I didn't use this logic to solve the problem, but I have to admit, I focused on the options that had 13 as the largest number to get to the answer
Being defeated is often only a temporary condition. Giving up is what makes it permanent.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 659
Joined: Mon Dec 14, 2009 8:12 amFollowed by: 3 members
Thanked: 32 times

by Gurpinder » Mon Sep 20, 2010 12:23 pm
Thx all.

Its clear now.

The "next #" is hypothetical. So the largest # is suppose to be the card SELECTED and that can only be 13.

: )
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1