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nikhilagrawal
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Statement I & II are clearly insufficient alone.nikhilagrawal wrote:Is x > y?
(1) root of x > y
(2) x^3 > y
c, but I think it shld be e
Combining I & II
if x is a positive integer
x^3 > x > sqrtx, therefore if sqrt x is greater than y, x will also be greater than y.
if x is a negative integer.
We cannot have this case because, sqrt x will always be positive.
if x is less than 1 and greater than 0
sqrtx > x > x^3, if x^3 is greater than y, then x will certainly be greater than y.
Sufficient.
Hence C.
Hope this helps. Let me know if you still have any doubts.

















