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Moving Walkway problem-- Reopening

Expert replies
by nadib002 » Tue May 03, 2011 4:14 pm
The 'moving walkway' is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill's average rate of movement for his trip along the moving walkway?

I know that this question has been answered in previous posts, but I am just not able to grasp the logic behind it. Please look at my explanation below and guide me in the right direction.

I read through the explanation for the question above, but the place where I am stuck is


Bill would have to first "chase and catch up". Therefore, I envisioned the problem as follows:

Chase and catch + be with the group

To Chase and Catch:


When bill starts, the group is already 120 ft ahead of him, so first he would have to cover the 120ft and then also cover the additional distance that the group would cover in the mean time

Bill's speed = 6 ft/sec

Distance to be covered = 120 ft

Relative Speed (since he is chasing) = 6-3 = 3ft/sec

Time to cover 120 ft = 120/3 = 40 secs.

But in the 40 secs that it took Bill to cover 120 ft, the Group must have already covered some distance.

Therefore the distance covered by the group in 40 secs = 40 *3 ft/sec(speed of group)= 120 ft

From above we know that the time it will take Bill to cover the remaining 120ft = 40secs ( I still use the relative speed here, because Bill has not caught up to the group yet)

Therefore total time taken by Bill to cover 240 ft = 40+40= 80 secs. But something does not seem right here.

Your help is needed here


Thank you
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Source: — Problem Solving |

by vineeshp » Tue May 03, 2011 6:35 pm
I am not sure what help you are looking for but when you work on such problems, you should not mix up actual speed and relative speed.

If you are working with the understanding that the group has covered some distance plus 120, then you need to take Bill's speed as 6, not 3.

If you decide to use relative speed, then you should stick to relative distance.

When Bill is at point 0, group is at 120. Relative distance is 120 feet.
Relative speed between Bill and the group is his walking speed of 3 feet per second.
So he will catch up with them in 120/3 = 40 seconds.

But in this 40 seconds, he has actually moved at 6 feet per second thereby covering a total of 240 feet.

Now his remaining distance is 60 feet and speed is 3 feet per second (that of the belt). So time taken is 20 seconds.

So he covers 300 feet in 40 + 20 seconds.
Av speed = 300/60 = 5 feet per second.

In your solution,
Therefore the distance covered by the group in 40 secs = 40 *3 ft/sec(speed of group)= 120 ft

From above we know that the time it will take Bill to cover the remaining 120ft = 40secs ( I still use the relative speed here, because Bill has not caught up to the group yet)
you have messed it up because you are talking about the distance travelled by Bill to cover the remaining 120 feet as a new set of 40 seconds which is wrong. Both the people cover the same distance of 120 to 240 in the same time Bill is catching up. So it is not an additional 40 seconds.

To put your mistake in perspective.
If Bill catches up with them in 80 seconds at his actual speed of 6 feet, he would have covered 480 feet which is beyond the belt. That is the red flag for you.

Hope I helped.
Vineesh,
Just telling you what I know and think. I am not the expert. :)
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by nadib002 » Tue May 03, 2011 8:12 pm
@vineeshp

Yes, you are absolutely correct!! I mixed the relative and the actual speeds.

I understand my mistake. Thank you for taking the time to explain. I really appreciate it.
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