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gmattesttaker2
- Legendary Member
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- Joined: Tue Feb 14, 2012 3:52 pm
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Hello,
Can you please help me with this :
Sue's trail mix is 30% nuts and 70% dried fruit. Jane's trail mix is 60% nuts and 40% chocolate chips. If the combined mixture of Sue and Jane's trails mix contains 50% nuts, what percent of the combined mixture is dried fruit?
OA: [spoiler]23.33%[/spoiler]
I tried to solve as follows:
S:
N--------N+DF-------DF
30%----------------70%
J:
N--------N+CC-------CC
60%----------------40%
Since the combined mixture contains 50% nuts, the other 50% is dry fruits plus chocolate chips
S+J:
DF-------DF+CC------CC
70%-------50%---------40%
DF/CC = 10/20 = 1/2
I wasn't sure though if is correct to set up the ratio this way. Can you please help?
Thanks,
Sri
Can you please help me with this :
Sue's trail mix is 30% nuts and 70% dried fruit. Jane's trail mix is 60% nuts and 40% chocolate chips. If the combined mixture of Sue and Jane's trails mix contains 50% nuts, what percent of the combined mixture is dried fruit?
OA: [spoiler]23.33%[/spoiler]
I tried to solve as follows:
S:
N--------N+DF-------DF
30%----------------70%
J:
N--------N+CC-------CC
60%----------------40%
Since the combined mixture contains 50% nuts, the other 50% is dry fruits plus chocolate chips
S+J:
DF-------DF+CC------CC
70%-------50%---------40%
DF/CC = 10/20 = 1/2
I wasn't sure though if is correct to set up the ratio this way. Can you please help?
Thanks,
Sri


















