kaplan 48

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kaplan 48

by resilient » Thu Apr 03, 2008 10:48 pm
If abc not = 0

Is a>0?


1.3a/b>0

2.b/c^2<0


qa is C, I got E


statement 1: a =1 b=1 or a and b can be neative also. Also need c so insufficient ( I dont understand solution at end of book)

statement 2 c is squared so it can have a positive or negative base. and lets be be neg or pos also. Coupling these two together, there is no sound evidence so E.. WHere does C in to play?
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Re: kaplan 48

by lunarpower » Fri Apr 04, 2008 1:53 am
Enginpasa1 wrote: 1.3a/b>0
you can ignore the '3': if 3a/b is positive, then a/b must also be positive.

interpretation: if the quotient a/b is positive, then a and b are either both positive or both negative.

therefore,
rephrase of statement 1: a and b have the same sign
Enginpasa1 wrote:2.b/c^2<0
the quantity c^2 is always positive, so let's rephrase this one to
b/(positive #) < 0
which means that b must be negative.

therefore,
rephrase of statement 2: b is negative

together, these statements mean that a must also be negative.
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