GMAT prep - a couple more

This topic has expert replies
Source: — Data Sufficiency |

Legendary Member
Posts: 559
Joined: Tue Mar 27, 2007 1:29 am
Thanked: 5 times
Followed by:2 members

by Cybermusings » Mon May 21, 2007 9:47 am
Free selection of 3 apples without conditions = 10C3 = 120
Selection of 2 red apples and 1 green apple = 7C2 * 3C1 = 21*3 = 63
Hence probability = 63/120 = 21/40