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Among a population of \(24,000\) people, \(80\) percent own a personal computer, \(88\) percent own a car, and \(72\)

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C

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Among a population of \(24,000\) people, \(80\) percent own a personal computer, \(88\) percent own a car, and \(72\) percent own both a personal computer and a car. If \(1\) person is to be randomly selected from the \(24,000\) people, what is the probability that the person selected will be one who owns a car but does NOT own a personal computer?

A. \(22/25\)
B. \(1/2\)
C. \(4/25\)
D. \(3/25\)
E. \(2/25\)

The OA is C
Source: — Problem Solving |