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Area of the circle = πr^2, where r = AC/2
When a triangle is inscribed in a circle with a side coinciding with the diameter of the circle, that triangle must be a right triangle, and the side coinciding with the diameter is the hypotenuse. Therefore, triangle ABC is a right triangle with hypotenuse AC. Furthermore, since angle BAC = 30 degrees, triangle ABC is a 30-60-90 triangle. So if BC = x, AB = x√3, then we have:



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