Water recession

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tonebeeze: Master | Next Rank: 500 Posts; Posts: 158; Joined: Mon Nov 02, 2009 5:49 pm; Thanked: 2 times; Followed by:3 members

Water recession

by tonebeeze » Tue Mar 08, 2011 2:16 pm

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The water level in a rectangular swimming pool measuring 60 feet by 25 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons)

a. 100
b. 250
c. 750
d. 1200
e. 5625

OA = e[/spoiler]

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Source: Beat The GMAT — Problem Solving | Tue Mar 08, 2011 2:16 pm

Tani: Legendary Member; Posts: 1255; Joined: Fri Nov 07, 2008 2:08 pm; Location: St. Louis; Thanked: 312 times; Followed by:90 members

by Tani » Tue Mar 08, 2011 2:58 pm

One foot deep in a 60 x 25 pool would be 1500 cubic feet. Half that is 750 cubic feet. (Note trap answer c!)

Each cubic foot represents 7.5 gallons so you need to get rid of 7.5 x 750 = 5625 gallons. (Note trap answer A if you divide by 7.5 instead of multiplying.)

Tani Wolff

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Jeff@TargetTestPrep: GMAT Instructor; Posts: 1462; Joined: Thu Apr 09, 2015 9:34 am; Location: New York, NY; Thanked: 39 times; Followed by:22 members

by Jeff@TargetTestPrep » Fri Jul 13, 2018 1:21 pm

tonebeeze wrote:The water level in a rectangular swimming pool measuring 60 feet by 25 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons)

a. 100
b. 250
c. 750
d. 1200
e. 5625

Using the fact that 6 in = 1/2 ft, the amount of water to be removed is 60 x 25 x 1/2 = 750 cu ft. Since 1 cu ft = 7.5 gallons, the number of gallons of water that must be removed is 750 x 7.5 = 5625.

Answer: E

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