akhilsuhag wrote:If |x| = |2y| what is the value of x - 2y ?
(1) x + 2y = 6
(2) xy > 0
|x| = |2y|.
Case 1: x=2y
In this case, x-2y = 2y-2y = 0.
Case 2: x=-2y
In this case, x-2y = -2y-2y = -4y.
Statement 1: x+2y = 6
Case 1: x=2y
Substituting x=2y into x+2y = 6, we get:
2y + 2y = 6
4y = 6
y = 2/3.
Case 1 is possible.
In Case 1, x-2y = 0.
Case 2: x=-2y
Substituting x=-2y into x+2y = 6, we get:
-2y + 2y = 6
0 = 6.
Case 2 is not possible.
Since only Case 1 is possible, x-2y = 0.
SUFFICIENT.
Statement 2: xy > 0
In other words, x and y have the SAME SIGN.
Case 1: x=2y
If y=1, then x=2, satisfying the constraint that x and y have the same sign.
Thus, Case 1 is possible.
In Case 1, x-2y = 0.
Case 2: x=-2y
If y=1, then x=-2, violating the constraint that x and y have the same sign.
If y=-1, then x=2, violating the constraint that x and y have the same sign.
Implication:
Case 2 is not possible..
Since only Case 1 is possible, x-2y = 0.
SUFFICIENT.
The correct answer is
D.
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