Its been solved before. Cant find the link
xy + z = x(y+z),
xy+z = xy+xz
xz-z=0
z(x-1) = 0
z=0 or x=1 must be true.
Choice E)
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gmataug08
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ok, I get it, in option A, z must be 0 but x need not be zero,so A is wrong.eracnos wrote:We can have z=0 and x = 1,2,3,4,5,6,7,8 ...... so A is wrongwhich of the following must be true?
(I guess this answers why my verbal score is so low

















