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Stumped on a Quant problem. Please help.

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Stumped on a Quant problem. Please help.

by blemming » Fri Feb 12, 2010 8:07 am
If the speed of X meters per second is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1km=1,000M)

*Note* I do have the correct answer to the question, but even with it, I still cannot understand how they are getting the answer.

Can anyone walk me through this? I've spent literally 45 minutes trying a number of different approaches. I will post the answer if needed.
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by sreak1089 » Fri Feb 12, 2010 8:23 am
It is simple. It is given that:

X (meters / second) = Y (Kilo meters / hour)

We also know that 1 Kilo meter = 1000 meters and 1 hour = 60 minutes = 60 * 60 seconds = 3600 seconds
Thus

X (meter / second) = Y (1000 meters) / (3600 seconds)
X (meter / second) = Y (1000/3600) (meter /second) Cance (meter/second) on both sides, you have

X = (1000 / 3600) * Y
Y = (3600/1000) * X
Y = (18/5) * X
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by ajith » Fri Feb 12, 2010 11:03 am
blemming wrote:If the speed of X meters per second is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1km=1,000M)

*Note* I do have the correct answer to the question, but even with it, I still cannot understand how they are getting the answer.

Can anyone walk me through this? I've spent literally 45 minutes trying a number of different approaches. I will post the answer if needed.
X meters per second = x/1000 kms/sec = x*3600/1000 km/hr = x*18/5 Km/hr =y

Y in terms of x is = x*18/5
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