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Three points A(1, 3), B(5, 0), C(3, 8) are the vertices of triangle ABC. If the line y =mx - m + 3 divides tr

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Three points A(1, 3), B(5, 0), C(3, 8) are the vertices of triangle ABC. If the line y =mx - m + 3 divides tr

by Max@Math Revolution » Wed Jan 15, 2020 11:10 pm

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[GMAT math practice question]

Three points A(1, 3), B(5, 0), C(3, 8) are the vertices of triangle ABC. If the line y =mx - m + 3 divides triangle ABC evenly, what is m?

A. -1
B. 1/3
C. 5/6
D. 7/8
E. 1
1.16ps.png
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Re: Three points A(1, 3), B(5, 0), C(3, 8) are the vertices of triangle ABC. If the line y =mx - m + 3 divides tr

by Max@Math Revolution » Sun Jan 19, 2020 5:52 pm
=>

y = mx – m + 3 = m(x - 1) + 3 passes through A(1, 3).
Since the line divides the triangle ABC evenly, it passes through the mid-point (4, 4) of BC.
Then the slope is (4 - 3) / (4 - 1) = 1/3.
Thus we have m = 1/3.

Therefore, B is the answer.
Answer: B
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