Q. A coin is tossed from the top of the cliff of height c, at time t = 0 secs. The coin follows the parabolic path h=at^2+bt+c, where h is the height from the ground at time t . What is the height of the stone at t = 5 sec?
1) 0.25a+0.5b+c=24
2) 0.04a+0.008b+0.0016c=1.5
The answer will be posted along with the solution on Sunday, Dcember 10th, 2006. Till then you can disucss your solutions here.
reference: www.scorechase.com
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1) 0.25a+0.5b+c=24
2) 0.04a+0.008b+0.0016c=1.5
The answer will be posted along with the solution on Sunday, Dcember 10th, 2006. Till then you can disucss your solutions here.
reference: www.scorechase.com
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