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Can someone solve this

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by hk_4u » Thu Jan 07, 2010 6:40 am
Two interpretations

1 -
((A^B)^C)^D = A^BCD

so

(10^100)^10^100 = 10^k

10^100000 = 10^k

k = 100000

2 - (A^B)^C^D = A^(B^C^D)

so
(10^100)^10^100 = 10^k

10^(100^10^100) = 10^k

k = (100^10^100)
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by truplayer256 » Thu Jan 07, 2010 9:48 am
(10^100)^(10^100)=10^k

Remember that we multiply exponents when they're raised to a power.

k=100*10^100=10^2*10^100=10^102
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by sadullaevd » Thu Jan 07, 2010 10:01 am
truplayer256 wrote:(10^100)^(10^100)=10^k

Remember that we multiply exponents when they're raised to a power.

k=100*10^100=10^2*10^100=10^102
Seems typo, could you the bold part plz,

IMO should k= 100*10*100= 100 000 (instead of ^ should be *)

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by truplayer256 » Thu Jan 07, 2010 5:11 pm
Why should k be 100*100*100, sadullaevd? I think you're making a common error.

10^100 quantity is being raised to 10^100 so it should equal 10^(100*10^100)=10^(102). As a result, k should equal 10^(102)
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by sadullaevd » Thu Jan 07, 2010 11:03 pm
my bad, it should be 10^102

misinterpreted the question,

thx,

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