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Source: — Data Sufficiency |
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by iamseer » Sun May 09, 2010 10:51 am
from 1:
Since x>r and y<s, we are subtracting a smaller quantity from a bigger quantity. So, (x - y) > (r - s) is always true.
Sufficient.

from 2:
xy<rs

x,y,r,s,xy,rs, Is (x - y) > (r - s)
3,4,5,3,12,15, NO
3,-4,5,3,-12,15, YES

Not Sufficient

IMO answer A
"Choose to chance the rapids and dance the tides"
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by gmatmachoman » Sun May 09, 2010 10:58 am
iamseer wrote:from 1:
Since x>r and y<s, we are subtracting a smaller quantity from a bigger quantity. So, (x - y) > (r - s) is always true.
Sufficient.

from 2:
xy<rs

x,y,r,s,xy,rs, Is (x - y) > (r - s)
3,4,5,3,12,15, NO
3,-4,5,3,-12,15, YES

Not Sufficient

IMO answer A
st 1 :x>r and y<s

can be reframed as -y>-sAddition is very much possible in equalities..( a lesson learnt from last post frm Harsha Bhai..courtesy Harsha!)

x-y>r-s

So sufficient.

for st 2: Seer has done his part...Good wrk bro!

SO pick A
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