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jainrahul1985
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Are you sure about the answer? Thanks
with 1) you know that y and z have the same sign, but you don't know anything about x
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Inequality
Source: Beat The GMAT — Data Sufficiency |
Firstly dont think A is the answer ..let's look at it
statement 1 :
y & z are either both negative or both positive
don't know anything about x . hence statement 1 insufficient
statement 2 :
x & y are either both negative or both positive
don't know anything about z . hence statement 2 insufficient
taking both the statement together
if from statement 1 , we say y,z are negative , then x is also negative which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
if from statement 1 , we say y,z are positive , then x is also positive which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
So , I will go with option C
statement 1 :
y & z are either both negative or both positive
don't know anything about x . hence statement 1 insufficient
statement 2 :
x & y are either both negative or both positive
don't know anything about z . hence statement 2 insufficient
taking both the statement together
if from statement 1 , we say y,z are negative , then x is also negative which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
if from statement 1 , we say y,z are positive , then x is also positive which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
So , I will go with option C
xyz ≠0 or x,y or z ≠0jainrahul1985 wrote:If xyz ≠0, is x (y + z) ≥ 0?
(1) |y + z| = |y| + |z|
(2) |x + y| = |x| + |y|
OA A
1) |y + z| = |y| + |z| so y & z have the same sign
but no info about the sign of x
so x(y+z) may be +ve or -ve Insuff
2) |x + y| = |x| + |y| so x & y have same sign
but no info about the sign of z Insuff
Combining x,y & z have same sign
xy + xz > 0 but ≠0
so either C or E
St1 doesn't say abt Xkstv wrote:xyz ≠0 or x,y or z ≠0jainrahul1985 wrote:If xyz ≠0, is x (y + z) ≥ 0?
(1) |y + z| = |y| + |z|
(2) |x + y| = |x| + |y|
OA A
1) |y + z| = |y| + |z| so y & z have the same sign
but no info about the sign of x
so x(y+z) may be +ve or -ve Insuff
2) |x + y| = |x| + |y| so x & y have same sign
but no info about the sign of z Insuff
Combining x,y & z have same sign
xy + xz > 0 but ≠0
so either C or E
St2 doesny say abt Z
Combining we get Inconsistent answers.
Examples :
x= -3,y=-2 z=-1
we have x (y + z)
: -3 *(-2-1) >0
when we have x=-3,y=-2,z=4
x (y + z) <0
Inconsistent ..Rite??
So pick E.
will you pl. cross check the OA again and post again?jainrahul1985 wrote:If xyz ≠0, is x (y + z) ≥ 0?
(1) |y + z| = |y| + |z|
(2) |x + y| = |x| + |y|
OA A
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Stuart@KaplanGMAT
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Perfect solution!debmalya_dutta wrote:Firstly dont think A is the answer ..let's look at it
statement 1 :
y & z are either both negative or both positive
don't know anything about x . hence statement 1 insufficient
statement 2 :
x & y are either both negative or both positive
don't know anything about z . hence statement 2 insufficient
taking both the statement together
if from statement 1 , we say y,z are negative , then x is also negative which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
if from statement 1 , we say y,z are positive , then x is also positive which we can derive from statement 2 because x,y are of the same sign
in this case x(y+z) > 0
So , I will go with option C
From (1), we know that y and z are the same sign, but know nothing about x.
From (2), we know that x and z are the same sign, but know nothing about y.
Together, we know that all 3 are the same sign.
So, when we multiply out the expression in the question, we're always going to get a non-negative answer: sufficient.
(I say non-negative because we could have x=y=z=0 and a final answer of 0.)
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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