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DS Set 14 problem

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Source: — Data Sufficiency |
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by ssmiles08 » Sat Jun 06, 2009 11:45 am
Choice 2 states that n > 2

n is not less than 2; otherwise n could be 1 which would make (1/10)^(0) = 1 which is not less than (1/10)

If n = 3

(1/10)^(2) < (1/10) -----satisfies condition 2

bring it to the question stem: (1/10)^3 < (1/100)?---->yes
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Re: DS Set 14 problem

by nervesofsteel » Sun Jun 07, 2009 9:13 am
axat wrote:If n is a positive integer, is (1/10) raised to n < 0.01 ?
(1) n > 2
(2) (1/10) raised to (n-1) < 0.1

OA : D

Don't know how.

[spoiler]1 is sufficient, and 2 brings me to n < 2, so answer could be E, but not D.[/spoiler]
2) (1/10) raised to (n-1) < 0.1 is nothing but (1/10) raised to n < 0.01
written in different form...

(1/10) ^ (n-1) = (1/10)^n/(1/10)

=> ((1/10)^n )*10 <0.1
=> (1/10)^n < 0.01

Thus B proves that (1/10)^n < 0.01
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