-
vinayreguri
- Junior | Next Rank: 30 Posts
- Posts: 29
- Joined: Sat May 07, 2011 6:16 am
Hi,
From(1): x/y + y/x = 2 =>(x^2+y^2)/xy = 2 => (x^2+y^2) -2xy = 0 =>(x-y)^2 = 0.
So, x=y
Sufficient
From(2): xz>yz => (x-y)z>0
If z>0, x>y
If z<0, x<y
Insufficient
Hence, A
