Hi jack0997,
This question is built around Absolute Value rules, so you can either approach it algebraically or with a bit of 'brute force' (meaning that most Absolute Value equations have more than one solution, so you just have to 'find' them all).
We're asked for the value of X.
1) |Y| <= 3X
While we don't know the value of Y, we do know that |Y| cannot be negative. Thus, |Y| is greater than, or equal to, 0. By extension, this means that 3X CANNOT be negative, so X CANNOT be negative. X is >= 0, but we don't know the exact value of X.
Fact 1 is INSUFFICIENT.
2) |5X - 1| ƒ = X ‚ + 7
When an equation contains an Absolute Value, there are likely to be two different possible values for X (depending on whether the value inside the absolute value is positive or negative)....
5X - 1= X + 7
4X = 8
X = 2
-(5X - 1) = X + 7
-5X + 1 = X + 7
-6 = 6X
X = -1
Thus, there are two solutions: -1 and 2.
Fact 2 is INSUFFICIENT
Combined, we know...
X >= 0
X = -1 or +2
There's only one solution that 'fits' both Facts: +2
Combined, SUFFICIENT
Final Answer: C
GMAT assassins aren't born, they're made,
Rich