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If \(\dfrac{z^2+6z+9}{z^2-9}=2,\) what is the value of \(z?\)

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by Vincen » Sun Jun 14, 2020 4:24 am

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Answers

A

B

C

D

E

Stats

Difficulty—

If \(\dfrac{z^2+6z+9}{z^2-9}=2,\) what is the value of \(z?\)

A. 9

B. 6

C. 3

D. -3

E. -9

[spoiler]OA=A[/spoiler]

Source: Princeton Review
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