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ds prep.

by galaxis09 » Mon Dec 03, 2012 3:26 pm
I know this problem has been posted before, but I cannot figure out where I am going wrong.
If 0<x<y, what is the value of (x+y)^2 / (x-y)^2


(1) x^2 + y^2 = 3xy

(2) xy = 3 .


When multiplied out we get x^2+2xy+y^2/x^2-2xy+y^2. Why can I not subtract the divisor and be left with 4xy. xy=3, 3*4=12
Source: — Data Sufficiency |

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by nisagl750 » Tue Dec 04, 2012 3:03 am
galaxis09 wrote:I know this problem has been posted before, but I cannot figure out where I am going wrong.
If 0<x<y, what is the value of (x+y)^2 / (x-y)^2


(1) x^2 + y^2 = 3xy

(2) xy = 3 .

Statement 1: We have (x^2+2xy+y^2) / (x^2-2xy+y^2)

subsitute the value from statement 1: x^2+y^2 = 3xy, we get
(3xy+2xy)/(3xy-2xy) = 5xy/xy = 5 (Since both x & y are positive)
Sufficient

Statement 2: We have (x^2+2xy+y^2) / (x^2-2xy+y^2)

subsitute the value from statement 2: xy=3, we get
(x^2+2*3+y^2) / (x^2-2*3+y^2)

= x^2+y^2+6/x^2+y^2-6
Since we do not know the values of X & Y
[spoiler]Do not assume x=1, y=3 as xy=3, It is nowhere written both are integers. x can be 1/3 and y can be 9[/spoiler]
Insufficient

IMO Answer is A
Wat is the OA?
Why can I not subtract the divisor and be left with 4xy. xy=3, 3*4=12
I didn't quite get your question. What from do you want to subtract the divisor?

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by Brent@GMATPrepNow » Tue Dec 04, 2012 6:53 am
galaxis09 wrote: If 0<x<y, what is the value of (x+y)^2 / (x-y)^2

(1) x^2 + y^2 = 3xy
(2) xy = 3
Target question: What is the value of (x+y)^2 / (x-y)^2

If we expand the numerator and denominator, we get [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2], so we can rephrase the target question.

Rephrased target question: What is the value of [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2]?

Statement 1: x^2 + y^2 = 3xy
Since x^2 + y^2 appears in the numerator and the denominator of the rephrased target question, we can replace x^2 + y^2 with 3xy to get:
What is the value of [3xy + 2xy] / [3xy - 2xy]?
This simplifies to be 5xy/xy, which equals 5 (since neither x nor y equal 0)
Since the expression evaluates to be one distinct value, we can answer the target question with certainty.
So statement 1 is SUFFICIENT

Statement 2: xy = 3
Since xy appears in the numerator and the denominator of the rephrased target question, we can replace xy with 3 to get:
What is the value of [x^2 + 2(3) + y^2]/[x^2 - 2(3) + y^2]?
This simplifies to be [x^2 + y^2 + 6]/[x^2 + y^2 - 6]
Can we simplify this expression further so that we get only one distinct value?
No.
The value of the expression can vary, depending on the values of x and y. To demonstrate this, consider these two case:
Case a: x=0.5, y=6 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = -13/11
Case b: x=1, y=3 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = -2
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent
Last edited by Brent@GMATPrepNow on Thu Dec 13, 2012 8:47 am, edited 2 times in total.
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by Brent@GMATPrepNow » Tue Dec 04, 2012 7:00 am
galaxis09 wrote: When multiplied out we get x^2+2xy+y^2/x^2-2xy+y^2. Why can I not subtract the divisor and be left with 4xy. xy=3, 3*4=12
I see that (x^2 + 2xy + y^2) - (x^2 - 2xy + y^2) = 4xy, but this doesn't mean that (x^2 + 2xy + y^2)/(x^2 - 2xy + y^2) = 4xy as well.

In one case we're subtracting and in the other case, we're dividing.

Similarly, 6/2 does not equal 6 - 2

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by nisagl750 » Tue Dec 04, 2012 8:07 am
Brent@GMATPrepNow wrote:
galaxis09 wrote: If 0<x<y,
Case a: x=3, y=1 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = 2
X can't be greater than Y as given in the question...
Case a: can be X=1/3, Y=9 which will give a different value for the above expression.

Either ways, Answer A

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by Brent@GMATPrepNow » Tue Dec 04, 2012 8:11 am
nisagl750 wrote:
Brent@GMATPrepNow wrote:
galaxis09 wrote: If 0<x<y,
Case a: x=3, y=1 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = 2
X can't be greater than Y as given in the question...
Case a: can be X=1/3, Y=9 which will give a different value for the above expression.

Either ways, Answer A
Ah, good catch - thanks.

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by sri_r » Thu Dec 13, 2012 1:25 am
Hi,

Is the correct answer C ?
My reasoning is:
from (1) => x^2+y^2 = 3xy
=> x^2 + y^2 -2xy = xy
=> (x-y)^2 = xy

from(2) => xy = 3
so (x-y)^2 = 3

Similarly (x+y)^2 = (x-y)^2 + 4xy
=> 3 + 4*3
=> 15

Therefore answer = 15/3 = 5




Brent@GMATPrepNow wrote:
galaxis09 wrote: If 0<x<y, what is the value of (x+y)^2 / (x-y)^2

(1) x^2 + y^2 = 3xy
(2) xy = 3
Target question: What is the value of (x+y)^2 / (x-y)^2

If we expand the numerator and denominator, we get [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2], so we can rephrase the target question.

Rephrased target question: What is the value of [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2]?

Statement 1: x^2 + y^2 = 3xy
Since x^2 + y^2 appears in the numerator and the denominator of the rephrased target question, we can replace x^2 + y^2 with 3xy to get:
What is the value of [3xy + 2xy] / [3xy - 2xy]?
This simplifies to be 5xy/xy, which equals 5 (since neither x nor y equal 0)
Since the expression evaluates to be one distinct value, we can answer the target question with certainty.
So statement 2 is NOT SUFFICIENT

Statement 2: xy = 3
Since xy appears in the numerator and the denominator of the rephrased target question, we can replace xy with 3 to get:
What is the value of [x^2 + 2(3) + y^2]/[x^2 - 2(3) + y^2]?
This simplifies to be [x^2 + y^2 + 6]/[x^2 + y^2 - 6]
Can we simplify this expression further so that we get only one distinct value?
No.
The value of the expression can vary, depending on the values of x and y. To demonstrate this, consider these two case:
Case a: x=3, y=1 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = 2
Case b: x=1, y=3 in which case [x^2 + 2xy + y^2] / [x^2 - 2xy + y^2] = -2
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent

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by Brent@GMATPrepNow » Thu Dec 13, 2012 8:55 am
sri_r wrote:Hi,

Is the correct answer C ?
My reasoning is:
from (1) => x^2+y^2 = 3xy
=> x^2 + y^2 -2xy = xy
=> (x-y)^2 = xy
You've determined that (x-y)^2 = xy, but we can also do some some work with (x+y)^2
(x+y)^2 = x^2 + 2xy + y^2
= 3xy + 2xy [I replaced x^2 + y^2 with 3xy)
= 5xy

So, (x+y)^2 = 5xy and (x-y)^2 = xy
This means that (x+y)^2 / (x-y)^2 = 5xy/xy = 5
Statement 1 is sufficient

Cheers,
Brent
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