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Source: — Data Sufficiency |
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by thephoenix » Thu May 06, 2010 12:12 pm
IMO E
Many of the great achievements of the world were accomplished by tired and discouraged men who kept on working
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by moliver » Fri May 07, 2010 1:14 pm
IMO E too
1) can be 0, -1, 1 insuf
2) nothing about y insuf
together x can be -1 or 1
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by debmalya_dutta » Fri May 07, 2010 1:17 pm
Insufficient information
Option E
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by 2011mbaspirant » Fri May 07, 2010 4:37 pm
The condition of y=x^2 along with x=y is true only for two values of x i.e. 1 and 0 and NOT for -1. Since statement 2 already says x=0 the only applicable value left for x is 1 -> y=x^2=1. Hence, both statements taken together gives us an exact solution. IMO the answer is C.
Please correct me if I am wrong.
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by debmalya_dutta » Fri May 07, 2010 5:06 pm
(S1) say y=x^2 => y = X * X
so if X = 4 ; Y is 16 , if X=3 ; Y=9 ........
I think you have missed the negative scenario.
2011mbaspirant wrote:The condition of y=x^2 along with x=y is true only for two values of x i.e. 1 and 0 and NOT for -1. Since statement 2 already says x=0 the only applicable value left for x is 1 -> y=x^2=1. Hence, both statements taken together gives us an exact solution. IMO the answer is C.
Please correct me if I am wrong.
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by moliver » Sat May 08, 2010 4:03 am
2011mbaspirant wrote:The condition of y=x^2 along with x=y is true only for two values of x i.e. 1 and 0 and NOT for -1. Since statement 2 already says x=0 the only applicable value left for x is 1 -> y=x^2=1. Hence, both statements taken together gives us an exact solution. IMO the answer is C.
Please correct me if I am wrong.
Hi 2011mbaaspirant, why do you say that -1 cannot be an answer?
Suppose case a
x=-1
y=1
from statement 1)
Y = X ^ 2 => 1 = (-1)^2

case 2
x=1
y=1
from statement 1)
Y = X ^ 2 => 1 = (1)^2

in both x is not equal to 0
so x can be 1 or -1

please correct me if I am wrong.
thanks!
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