j_shreyans wrote:Hi Brent ,
our question is:
p + pz = p
if we take out the p from the above we will have
p(1+z)=p
then 1+z=1
then z=0 so this should be our target question right?
So by the above target question only statement 2 is sufficient.
Please suggest and correct me if i am wrong.
Thanks
Shreyans
Good idea, Shreyans.
However, there's a slight problem with your conclusion.
We have:
p(1+z)=p
If we divide both sides by p, we get: 1+z=1, which means
z = 0 is a possible solution
HOWEVER, when we divide both sides by p, we must realize that p might equal 0. Notice that, if p = 0, then
p(1+z)=p.
So,
p = 0 is another possible solution.
So, we have two possible solutions:
z = 0 and
p = 0
So if either of these is the solution, then
pz = 0
That's why I REPHRASED the target question as:
Does pz = 0?
BIG TAKEAWAY, when dividing both sides of an equation by a variable, we must consider the possibility that we may be dividing both sides by ZERO.
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
