badresh70 wrote:Hi Mitch,
Can you please explain it in some different manner or may be with another example.
I did not understood from the current example.
Thanks,
Badresh
To illustrate why statement 1 is sufficient:
The most expensive item = 50.
20% discount = .2*50 = 10.
The maximum sum of the prices of the 2 other items = 20+20 = 40.
10% discount = .1*40 = 4.
20% discount + 10% discount = 10+4 = 14.
Total of the regular prices = 50+20+20 = 90.
A 15% discount would be = .15*90 = 13.5.
Since 14>13.5, the total discount is greater than 15%.
The prices of the other 2 items can only be decreased, since the next most expensive item can't be more than $20.
Let the sum of the prices of the 2 other items = 20+10 = 30.
10% discount = .1*30 = 3.
20% discount + 10% discount = 10+3 = 13.
Total of the regular prices = 50+20+10 = 80.
A 15% discount would be = .15*80 = 12.
Since 13>12, the total discount is greater than 15%.
Notice that as the sum of the prices of the other 2 items decreases, the difference between the total discount and the 15% discount
increases.
Thus, the total discount will always be greater than 15%.
Last edited by
GMATGuruNY on Mon May 23, 2011 11:21 am, edited 1 time in total.
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