Max@Math Revolution wrote:
If x and y are positive integers, what is the remainder when 3^{4x+1}+y is divided by 10?
1) x=2
2) y=3
Recall that the remainder when a number is divided by 10 depends on the units digit of the number. Thus if we can determine the units digits of 3^{4x+1} + y, we can determine the remainder (since it will just be the units digit).
Statement One Alone:
x = 2
Therefore, 3^{4x+1} + y = 3^9 + y. Without knowing the value of y, we can't determine the units digit of 3^{4x+1} + y. Statement one alone is not sufficient to answer the question.
Statement Two Alone:
y = 3
Therefore, 3^{4x+1} + y = 3^{4x + 1} + 3. It seems the statement is not sufficient since we don't know the value of x. However, we may recall that the base of 3, has a repeating units digit pattern of 3-9-7-1 when it is raised to a positive integer power. Thus, 3 raised to a power that is a multiple of 4 will always end in a 1 and furthermore 3 raised to a power that is 1 more than a multiple of 4, will always end in a 3.
Thus, without even knowing the value of x, we can determine that 3^(4x+1) will always end in a 3. Therefore, the units digit of 3^{4x+1} + y = 3 + 3 = 6. Statement two alone is sufficient to answer the question.
Answer: B
Jeffrey Miller
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