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gustavogalli
- Newbie | Next Rank: 10 Posts
- Posts: 2
- Joined: Mon Jul 23, 2018 2:24 pm
Statement 1: x > y-2gustavogalli wrote:(1) x - y > -2
(2) x - 2y < -6
If y=2 and x= 1, is 1*2 > 0? Yes.
If y= -1 and x = 1, is 1*(-1) > 0? No.
Since the answer is YES in the first case but NO in the second case, INSUFFICIENT.
Statement 2: x < 2y-6
If y=1 and x = -10, is 1*(-10) > 0? No.
If y = 10 and x = 1, is 1*10 > 0? Yes.
Since the answer is NO in the first case but YES in the second case, INSUFFICIENT.
Statements 1 and 2 combined:
Linking together the two statements, we get:
y-2 < x < 2y-6
y-2 < 2y-6
y > 4.
Since y > 4 and x > y-2, we know that x > 2.
Thus, x and y are both positive.
SUFFICIENT.
The correct answer is C.
Another way to combine the two statements:
Inequalities can be ADDED TOGETHER.
One constraint:
When we add the inequalities together, the <> must face the SAME DIRECTION in each inequality.
Adding together x - y > -2 and -6 > x - 2y, we get:
x - y + (-6) > -2 + x - 2y
- y - 6 > -2 - 2y
y > 4.
Same result as in the solution above.
