Kunal,

There seems to be some real issue with the logic presented. One thing we have to understand is that the 2 statements presented are true no matter what. Their outcomes might have different results for the question - and that is something we have to deal with in DS.

I will try to deal with your confusion as well.

Question - Is x<0? In essence, this asks if x is negative.

Statement 1 - -2x>0

This statement as given in the question is fully true. We can't deny it as not being plausible. Now in this case, statement 1 can be truly only if the 2 integers in the product have the same symbol ie; negative * negative will ensure that the product is greater than 0 and positive*positive will ensure that the poroduct is greater than 0.

Since -2 is a negative integer, this statement conclusively tells me that -2x>0 only if x is also negative. Sufficient.

If x was 0, then -2x would be equal to 0 and not greater than 0, which means we are contradicting the statement.

Statement 2 - x^3 < 0

This statement tells me that a number raised to the power 3 is less than 0. This can only happen if the number is negative (regardless whether it is a fraction or an integer). Sufficient

If x was 0, then x^3 would be equal to 0 and not less than 0, which means we are contradicting the statement.

Answer D

Regards
Anup

Thanks Anup. you really made it easy for me to understand the question.