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Is 2y+3x−5=0 the equation of line q?

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by Vincen » Tue Sep 12, 2017 11:04 am
Is 2y+3x−5=0 the equation of line q?

(1) The x-intercept of line q is (5,0).

(2) The slope of line q is 2/3.

D is the OA.

How can I know the slope of the given equation?
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Source: — Data Sufficiency |

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by ErikaPrepScholar » Tue Sep 12, 2017 11:20 am
To find the slope (and the y-intercept), we need to rearrange the equation to slope-intercept form: y=mx+b, where m = slope and b = y-intercept.

2y+3x-5 = 0
2y = -3x + 5
y = -(3/2)x + 5/2

So we know that the slope of the line is -3/2 and the y-intercept is (0, 5/2).

Statement 1 tells us that the y-intercept of q is NOT (0, 5/2), so this cannot be the equation. Sufficient.

Statement 2 tells us that the slope of q is NOT -3/2, so this cannot be the equation. Sufficient.

The correct answer is D.
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