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Is d negative?

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Source: — Data Sufficiency |
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by vineeshp » Sun Mar 20, 2011 6:58 pm
C, Both statements together are sufficient.

Stmt 1:
e + d = -12

e = -13, d =1 works
So does, e = -11 and d = -1.
Not sufficient.

Stmt 2:
e - d < -12

e = 1, d = 14 works
e = -15, d = -1 works.

Combined.

Substitute for e in the inequality from the given equation.
e + d = -12 ==> e = -d -12

-d - 12 -d < -12. can be solved to get d's sign.
Vineesh,
Just telling you what I know and think. I am not the expert. :)
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by RadiumBall » Sun Mar 20, 2011 8:40 pm
Thanks the OA is C

But I have a question if we continue by substitution method for C then again 'd' can be
-ve i.e. -25 - (-12) < -12 or
+ve i.e. -1 - (+12) < -12

So I thought the answer is E, how do we correctly make a decision here?
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by Anurag@Gurome » Sun Mar 20, 2011 9:28 pm
RadiumBall wrote:Thanks the OA is C

But I have a question if we continue by substitution method for C then again 'd' can be
-ve i.e. -25 - (-12) < -12 or
+ve i.e. -1 - (+12) < -12

So I thought the answer is E, how do we correctly make a decision here?
Remember that you have to take 'e' and 'd' such that e + d = -12.
When you take e = -25 and d = -12, e+d = -37 which is not equal to -12.
So your choice of 'e' and 'd' is not correct in first case.
Try again. No negative value of d will satisfy both the statements combined.
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