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taneja.niks
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x2-y2=0taneja.niks wrote:another one guys
If x is an integer ,is x even?
1. x2-y2=0
2. x2+y2=18
let x=2, then y=2 or -2 [x is even]
x=3, then y=3 or -3 [x is odd]
INSUFFICIENT
x2+y2=18
x=3, y=3 or -3 [x is odd]
x=4, y=root(2) [x is even]
INSUFFICIENT
combining both, we get,
2x^2 = 18,
x^2=9
x = 3 or -3
answer is NO.
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