OG 11 DATA SUFFICIENCY QNO 145

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OG 11 DATA SUFFICIENCY QNO 145

by georgy » Wed May 13, 2009 4:22 am
GMATONIANS,

PL HELP

IS 1/P > R/(R^2+2) ?

(1) P = R
(2) R > 0

ANS IS C.
I UNDERSTOOD HOW OG 11 ARRIVED AT THIS,BUT I DONT UNDERSTAND WHY MY METHOD IS WRONG, WHICH IS

SUBSTITUTING (1),
1/R > R / (R^2 + 2)
CROSS MULTIPLYING
1>R^2/(R^2 +2)
OR
(R^2 +2)/R^2 > 1
WHICH IS TRUE FOR ALL CASES OF R, + OR - , HENCE ANS IS A

WELL,WHY NOT?
Source: — Data Sufficiency |

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Re: OG 11 DATA SUFFICIENCY QNO 145

by Vemuri » Wed May 13, 2009 4:37 am
Because you did not consider the negative value of R. What if R<0, then the inequality will be:

R^2/(R^2+2)>1, which cannot be correct because (R^2+2) > R^2.

We need the second statement as well to answer the question.

Hope that helps.

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Re: OG 11 DATA SUFFICIENCY QNO 145

by Ian Stewart » Wed May 13, 2009 12:45 pm
georgy wrote:
SUBSTITUTING (1),
1/R > R / (R^2 + 2)
CROSS MULTIPLYING
1>R^2/(R^2 +2)
Ron just discussed this in another thread, but you can't 'cross-multiply' with inequalities unless you know whether your denominators are positive or negative. When you 'cross-multiply', you're really multiplying on both sides by both denominators. So in the above, when you cross-multiplied, you were multiplying on both sides by r^2 + 2, and by r. Well, r^2 + 2 is certainly positive, so no problem there, but r could be positive or could be negative. If r is negative, you'd need to reverse the inequality when you multiply by r on both sides. That's why you need the second statement, which guarantees that r is positive, and that you can multiply by r on both sides without needing to worry about reversing the inequality.
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OG 11 DS 145

by georgy » Mon May 18, 2009 5:04 am
I SEE,LEARNED SOMETHING NEW TODAY... THANK YOU

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by iamcste » Tue May 19, 2009 11:22 am
Using stament 1, can this be simplified to


2/R>0

or have I over simplified it :D

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by Ian Stewart » Tue May 19, 2009 3:56 pm
iamcste wrote:Using stament 1, can this be simplified to


2/R>0

or have I over simplified it :D
Yes, that's perfect - you can even go further than that.

In detail, when we use Statement 1, we can rephrase the question, by rewriting it algebraically. Note that all we're doing is restating the question in different ways; what we're hoping to find is either:

-something we know to be true, like 2 > 0. Then we'll know we have sufficient information;
-something we don't know is true, like r > 0. Then we'll know we don't have sufficient information, and we'll know exactly what information we need.

Is 1/p > r/(r^2 + 2) ?

Using S1, this becomes:

Is 1/r > r/(r^2 + 2) ?

We can multiply by r^2 + 2, since we know that r^2 + 2 must be positive:

Is (r^2 + 2)/r > r ?
Is (r^2/r) + (2/r) > r ?
Is r + (2/r) > r ?
Is 2/r > 0 ?
Is r > 0?

And now we see why we need Statement 2 as well.
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by iamcste » Wed May 20, 2009 9:45 am
Ian Stewart wrote:
iamcste wrote:Using stament 1, can this be simplified to


2/R>0

or have I over simplified it :D
Yes, that's perfect - you can even go further than that.

In detail, when we use Statement 1, we can rephrase the question, by rewriting it algebraically. Note that all we're doing is restating the question in different ways; what we're hoping to find is either:

-something we know to be true, like 2 > 0. Then we'll know we have sufficient information;
-something we don't know is true, like r > 0. Then we'll know we don't have sufficient information, and we'll know exactly what information we need.

Is 1/p > r/(r^2 + 2) ?

Using S1, this becomes:

Is 1/r > r/(r^2 + 2) ?

We can multiply by r^2 + 2, since we know that r^2 + 2 must be positive:

Is (r^2 + 2)/r > r ?
Is (r^2/r) + (2/r) > r ?
Is r + (2/r) > r ?
Is 2/r > 0 ?
Is r > 0?

And now we see why we need Statement 2 as well.
Thanks Ian!