What is one possible solution of the quadratic equation (x + a)(x - b) = 0?
(1) a = 4
(2) b = 3
Isnt each statement not sufficient ?
(1) a = 4
(2) b = 3
Isnt each statement not sufficient ?
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One possible solution
Source: Beat The GMAT — Data Sufficiency |
OA D
Source MGMAT CAT
I meant to say how is each statement sufficient? My pick was E
Source MGMAT CAT
I meant to say how is each statement sufficient? My pick was E
neoreaves wrote:I AGREE ,....answer should be D ...what is the source of the question though ?
we are only asked to find one possible solution ....from the equation there are two
x = -a or x = b
if we can find either one of them then we are done
1) gives us value of a ...so gives us one possible solution so its sufficient
2) similarly gives us one possible solution so sufficient
x = -a or x = b
if we can find either one of them then we are done
1) gives us value of a ...so gives us one possible solution so its sufficient
2) similarly gives us one possible solution so sufficient
if a's value is given in statement 1 , we can solve for the first part of the quadratic i.e. (x + a)
But what about the second half ? i.e., (x-b) ?
isn't (x+a)(x-B) a complete quadratic eqn whose answer would depend on a AND b?
But what about the second half ? i.e., (x-b) ?
isn't (x+a)(x-B) a complete quadratic eqn whose answer would depend on a AND b?
neoreaves wrote:we are only asked to find one possible solution ....from the equation there are two
x = -a or x = b
if we can find either one of them then we are done
1) gives us value of a ...so gives us one possible solution so its sufficient
2) similarly gives us one possible solution so sufficient
a quadratic has 2 solutions.. we are asked to find any 1 solution.. so if we know a or b we get one solution.. hence both statements individually answers..
