If you look at statement 2, you already know that you can figure out the problem because every variable is solved for you. This leaves answer choices B and D

For statement 1, you can just plug in numbers and you should be able to solve it.

Answer is D.

Is x – y > r – s?
(1) x > r and y < s

x-y > r-s ??
or
x-r > y-s

x-r is +ve number from 1
y-s is -ve number from 1

so x-y is greater then y-s

Guyz!!

I think everyone missed the point here!! yogesh asks for a sytematic approach...plugging is gud but as yogesh rightly points out that u may miss some cases.

Can anyone please advice on the best way to tackle such questions

eg14. Is x – y > r – s?
(1) x > r and y < s?
(2) y = 2, s = 3, r = 5, and x = 6.

I wud try to giv a systematic approach here..

Given: from 1. x > r and y < s

i wud make one expression +ve and one -ve. then i can confidently say that +ve > -ve

so x-r>0 and y-s<0 from whats given...

now simple...x-r is +ve and y-s is -ve
so x-r>y-s ....true!!

thats it...this can be applied to all such questions...finally it boils down to getin the expression in the apt form.

hope it helps!!

for statement 1
x>r --> x>r
y<s --> -y>-s
add then up and x-y>r-s
so it holds by itself

why is the problem deleted??