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Percent of revenue from sales of tables

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by gmattesttaker2 » Sun May 18, 2014 10:26 am
Hello,

Can you please help with this:

Company Z only sells chairs and tables. What percent of its revenue in 2008 did Company Z derive from its sales of tables?

1) In 2008, the average price of tables sold by Company Z was 10% higher than the average price of chairs sold by Company Z

2) In 2008, Company Z sold 20% fewer tables than chairs

OA: C


Thanks,
Sri
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Source: — Data Sufficiency |

by GMATGuruNY » Sun May 18, 2014 12:50 pm
gmattesttaker2 wrote:Hello,

Can you please help with this:

Company Z only sells chairs and tables. What percent of its revenue in 2008 did Company Z derive from its sales of tables?

1) In 2008, the average price of tables sold by Company Z was 10% higher than the average price of chairs sold by Company Z

2) In 2008, Company Z sold 20% fewer tables than chairs
Statement 1: In 2008, the average price of tables sold by Company Z was 10% higher than the average price of chairs sold by Company Z
Test one case that also satisfies statement 2.
Case 1:
Price per chair = $10, number of chairs sold = 10, yielding $100 in revenue.
Price per table = $11, number of tables sold = 8, yielding $88 in revenue.
In this case, (table revenue)/(total revenue) = 88/188.

Test one case that doesn't satisfy statement 2.
Case 2:
Price per chair = $10, number of chairs sold = 100, yielding $1000 in revenue.
Price per table = $11, number of tables sold = 8, yielding $88 in revenue.
In this case, (table revenue)/(total revenue) = 88/1088.

Since (table revenue)/(total revenue) can be different values, INSUFFICIENT.

Statement 2: In 2008, Company Z sold 20% fewer tables than chairs
Case 1 also satisfies statement 2.
In Case 1, (table revenue)/(total revenue) = 88/188.

Test one case that satisfies statement 2 but doesn't satisfy statement 1.
Case 3:
Price per chair = $1, number of chairs sold = 10, yielding $10 in revenue.
Price per table = $2, number of tables sold = 8, yielding $16 in revenue.
In this case, (table revenue)/(total revenue) = 16/26.

Since (table revenue)/(total revenue) can be different values, INSUFFICIENT.

Statements combined:
Case 1 satisfies both statements.
In Case 1, (table revenue)/(total revenue) = 88/188.

Test one more case that satisfies both statements.
Case 4:
Price per chair = $20, number of chairs sold = 100, yielding $2000 in revenue.
Price per table = $22, number of tables sold = 80, yielding $1760 in revenue.
In this case, (table revenue)/(total revenue) = 1760/3760 = 176/376 = 88/188.

Since (table revenue)/(total revenue) is the same value in each case, SUFFICIENT.

The correct answer is C.
Last edited by GMATGuruNY on Sun May 18, 2014 5:38 pm, edited 1 time in total.
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by [email protected] » Sun May 18, 2014 2:12 pm
Hi Sri,

This question can also be solved algebraically, but you have to set everything up carefully (since there are 4 variables):

We're told that a company sells tables and chairs. We're asked what percent of TOTAL REVENUE was the REVENUE FROM TABLES.

C = number of chairs sold
T = number of tables sold
X = price of a chair
Y = price of a table

The question asks us to solve this: (TY)/(TY + CX) = ?

Fact 1: The average price of tables sold was 10% higher than the average price of chairs sold.

This translates into: Y = 1.1X

We can substituted in this value.....

(T)(1.1X)/[(T)(1.1X) + CX]

....but the question still has too many unknowns and we can't simplify it.
Fact 1 is INSUFFICIENT

Fact 2: Company Z sold 20% fewer tables than chairs.

This translates into T = .8C

We can substitute in this value, but we run into the same problem that we did in Fact 1: too many unknowns.
Fact 2 is INSUFFICIENT

Combining, we know....
Y = 1.1X
T = .8C

Let's substitute both into the original question:

(.8C)(1.1X)/[(.8C)(1.1X) + CX]

Now, let's simplify....

.88CX/[.88CX + CX]

.88CX/1.88CX

The CX cancels out...

.88/1.88 = 88/188

Since we end up with a value (and it's just one option)....Combined, SUFFICIENT.

Final Answer: C

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Rich
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by ceilidh.erickson » Tue May 20, 2014 8:54 am
It's certainly not necessary to solve this algebraically. Since revenue is a function of number of items sold x price, if we want to know the proportion of revenue from tables, we need to know two things:

1) the proportion of price of chairs to price of tables
2) the proportion of number of chairs sold to number of tables sold

We don't need to solve for actual values - if we have these two proportions, we'll know the proportion of total revenue. Statement 1 gives us the first proportion we need, and statement 2 gives us the second. Thus, we need both statements together.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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