BlueDragon2010 wrote:If x is an integer, is 9^x + 9^-x = b?
1) 3^x + 3^-x = sq.root(b+2)
2) x > 0
Memorize the following quadratic indentities:
(a+b)² = a² + 2ab + b²
(a-b)² = a² - 2ab + b²
(a+b)(a-b) = a² - b².
Statement 1: 3^x + 3^-x = √(b+2)
Squaring both sides, we get:
(3^x + 3^-x)² = b+2
The identity in red can serve to rephrase the lefthand side:
(a+b)² = a² + 2ab + b²
(3^x + 3^-x)² = (3^x)² + 2(3^x)(3^-x) + (3^-x)².
Simplifying further, we get:
(3^x)² + 2(3^x)(3^-x) + (3^-x)²
= 3^(2x) + 2(3^0) + 3^(2*-x)
= 9^x + 2 + 9^(-x).
Since the lefthand side can be rephrased as 9^x + 2 + 9^(-x), we get:
9^x + 2 + 9^(-x) = b+2
9^x + 9^(-x) = b.
SUFFICIENT.
Statement 2: x > 0
No information about b.
INSUFFICIENT.
The correct answer is
A.
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