6 persons seat themselves at round table. What is the probability that 2 given persons are adjacent?
(A) 1/5
(B) 2/5
(C) 1/10
(D) 1/7
(E) 2/15
(A) 1/5
(B) 2/5
(C) 1/10
(D) 1/7
(E) 2/15
unless I'm mistaken (could be since I'm really tired haha) the problem should be pretty straight forward, and the answer should be 2/5
for any given 2 people, regardless of where the first person sits, the second person has 2 possible ways to be next to the first person (L & R of the person) and 5 possible ways of seating himself total = 2/5
