If |X| + |y|= -x-y & xy does not equal 0, which of the following must be true?
a)x+y>0
b)x+y<0
c)x-y>0
d)x-y<0
e)x^2 - y^2>0
OA b
a)x+y>0
b)x+y<0
c)x-y>0
d)x-y<0
e)x^2 - y^2>0
OA b
Well, you start by analyzing |x| + |y|. Since the absolute value of any number is always positive or equal to 0, you get that |x| + |y| >=0. Now, since xy does not equal 0, both terms must not equal zero. So this means that both |x| and |y| are not equal to zero. This leaves us with |x| + |y| > 0. Now, we get that |x| + |y|= -x-y. This means that - x - y > 0, ot that x + y < 0.
B is your answer.
