Hi,
k/6 + m/4 =t/12.
So, t = 2k+3m
From(1):k is a multiple of 3.
So, k = 3p where p is an integer.
So, t = 2(3p)+3m = 3(2p+m)
So, t is a multiple of 3. So, t and 12 have a common factor of 3.
Sufficient
From(2):m is a multiple of 3
if k=1 and m = 3, then t=11. common factor of t and 12 is 1
if k=1 and m = 6, then t=20. common factor of t and 12 is 4
Not sufficient to tell whether the common factor is 1 or greater than 1
Hence, A
divisibility
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
Frankenstein
- Legendary Member
- Posts: 1448
- Joined: Tue May 17, 2011 9:55 am
- Location: India
- Thanked: 375 times
- Followed by:53 members
-
Gurpinder
- Legendary Member
- Posts: 659
- Joined: Mon Dec 14, 2009 8:12 am
- Thanked: 32 times
- Followed by:3 members
thanks buddy!
to make a note...
y = any number.
m and p are factors of y
so can i make a note that: factor m + or - factor p = x
and that as long as M and P are factors of Y, then x and Y will aways have factors greater than 1.
to make a note...
y = any number.
m and p are factors of y
so can i make a note that: factor m + or - factor p = x
and that as long as M and P are factors of Y, then x and Y will aways have factors greater than 1.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
-
Frankenstein
- Legendary Member
- Posts: 1448
- Joined: Tue May 17, 2011 9:55 am
- Location: India
- Thanked: 375 times
- Followed by:53 members
Hi,
I don't understand your question precisely.
If you meant to say m and p are factors of y
and m + p =x, then x and y will always have factors more than 1.. this is incorrect
Consider y=12
let m=3, p=4
x = m+p = 7
x(7) and y(12) have only '1' as common factor.
I don't understand your question precisely.
If you meant to say m and p are factors of y
and m + p =x, then x and y will always have factors more than 1.. this is incorrect
Consider y=12
let m=3, p=4
x = m+p = 7
x(7) and y(12) have only '1' as common factor.
Cheers!
Things are not what they appear to be... nor are they otherwise
Things are not what they appear to be... nor are they otherwise
-
Gurpinder
- Legendary Member
- Posts: 659
- Joined: Mon Dec 14, 2009 8:12 am
- Thanked: 32 times
- Followed by:3 members
yeah that is what i meant....but i guess that wrong....
so whats the generalization from the question?
or did you simply plugin numbers?
so whats the generalization from the question?
or did you simply plugin numbers?
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
