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Bakery Question

Expert replies
by briology » Thu Oct 13, 2011 4:59 pm
A certain bakery ran a promotion: a customer can buy x donuts for the regular price of $15 total and get 3 donuts free. If the donut price per dozen during the promotion is $2 less than the normal donut price per dozen, what is x?

A 15
B 18
C 21
D 25
E 30

OA after some answers.
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Source: — Problem Solving |

by fcabanski » Thu Oct 13, 2011 6:38 pm
P1 is the normal price.
P2 is the promotion price.

X*P1=15 : X purchased at the normal price for $15
(X+3)*P2 = 15 : But you get 3 more, so X+3 times whatever the promotion price is also $15

Now deal with those dozen. A dozen purchased at the promotion price (P2) is $2 less than a dozen purchased at the normal price (P1):

12P1 - 2 = 12P2

Three equations, three unknowns. Solve it with algebra, or substitute in the different answers to check if they work.

In each case use the given x to solve two of the equations, then check those values in the third equation.

If x=15

(x+3)*P2 = 15 substitute 18P2 = 15 divide P2 = 5/6

12P1 - 2 = 12P2 substitute and add 2 to both sides 12P1 = 10+2 = 12 so P1 = 1

Check with the third equation x*P1=15 substitute 15*1=15

This is the correct answer.

Try the others just for fun.
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by GmatKiss » Fri Oct 14, 2011 8:05 am
briology wrote:A certain bakery ran a promotion: a customer can buy x donuts for the regular price of $15 total and get 3 donuts free. If the donut price per dozen during the promotion is $2 less than the normal donut price per dozen, what is x?

A 15
B 18
C 21
D 25
E 30

OA after some answers.
substitute for x,

it goes like,

15+3 = 15$
18=15$ --------- (A)
12=10$ [2/3 of (A)]

which is 2 less than the normal price :)

IMO: A
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