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williamthesituation
- Newbie | Next Rank: 10 Posts
- Posts: 8
- Joined: Mon Jan 25, 2010 4:12 pm
If x^3 -x = p, and x is odd, is p divisible by 24
p = (x-1)x(x+1)
We have two evens and one odd, the two evens have at least three 2's as prime factors, so to make 24 we need a 3.
My question is why does X which is odd have to be a multiple of 3, why can't X be 1, and then in that case we would only have 0,1,2 sequentially...... Is there some rule that says you can't have zeros or 1's in questions like these?
The book states in any set of 3 consecutive integers, one of the integers will be a multiple of 3, what if the 3 integers were 0,1,2 or -1,0,1???
Can someone shed light into whether or not you can go into negatives on questions like these or maybe i'm missing something else all together..
Thanks.
p = (x-1)x(x+1)
We have two evens and one odd, the two evens have at least three 2's as prime factors, so to make 24 we need a 3.
My question is why does X which is odd have to be a multiple of 3, why can't X be 1, and then in that case we would only have 0,1,2 sequentially...... Is there some rule that says you can't have zeros or 1's in questions like these?
The book states in any set of 3 consecutive integers, one of the integers will be a multiple of 3, what if the 3 integers were 0,1,2 or -1,0,1???
Can someone shed light into whether or not you can go into negatives on questions like these or maybe i'm missing something else all together..
Thanks.













