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Source: — Data Sufficiency |

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by Rahul@gurome » Tue Oct 05, 2010 4:23 am
(1) 22 = 2 * 11 and 33 = 3 * 11. Since xyz is divisible by 22 and 33, so xyz has the factors 2, 3 and 11. But this info is NOT SUFFICIENT to answer the question.

(2) 72 = 2^3 * 3^2, so yz has the factors 2 and 3. But this info is again NOT SUFFICIENT to answer the question.

Combining (1) and (2), also we cannot say whether x is divisible by 11.

[spoiler]The correct answer is (E).[/spoiler]
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by goyalsau » Tue Oct 05, 2010 4:25 am
Is it E,
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by shovan85 » Tue Oct 05, 2010 4:37 am
from 1: xyz multiple of 22 and 33. So we can say xyz = 66k (where k = 1, 2, 3, ...)
66 = LCM(22,33). But we cannot say whether x is a multiple of 11. Not Suff.

from 2: yz is a multiple of 72. So we can say yz=72k' (k'=1,2,3,....)
Still Not sufficient.

Combine 1 and 2 :

xyz = x(yz) = 66K
=> x(72k') = 66k
=> x(12k') = 11k
=> x = 11k/12k' Hence Not Suff.

IMO

E
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by Yanat » Tue Oct 05, 2010 8:23 am
IMO it is E
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