If x, y and k are integers, is xy divisible by 3?
(1) y = 2^16 - 1 (EDIT)
(2) The sum of the digits of x equals 6^k
The OA is only S1 is sufficient.
they said (2) isn't sufficient b/c if k=1, xy is div by 3... but if k=0, it isn't.... how can you have the sum of the digits add up to zero and still satisfy the fact that X=6^k??
(1) y = 2^16 - 1 (EDIT)
(2) The sum of the digits of x equals 6^k
The OA is only S1 is sufficient.
they said (2) isn't sufficient b/c if k=1, xy is div by 3... but if k=0, it isn't.... how can you have the sum of the digits add up to zero and still satisfy the fact that X=6^k??
Last edited by odannyboi on Tue Sep 21, 2010 5:11 pm, edited 1 time in total.
