Interesting GMATFix Problem-2

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Interesting GMATFix Problem-2

by arora007 » Tue Sep 21, 2010 12:47 pm
If Z^2 < z and y is a negative integer, is x greater than the average of y and z?
1) x- |y| >z
2) xz > 0
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by clock60 » Tue Sep 21, 2010 11:22 pm
here i got D but not too sure,
first to st 2 as it seems easier
(2)x*z>0 we know that 0<z<1 ( i mean +ve fraction) so x is also +ve. and y -ve integer
the difference between (y+z) always-ve, and x is +ve, so x>(y+z)/2. as +ve>-ve, the answer is yes

(1) x-|y|>z, z>0 so x-|y|>0, and x>|y|, |y|>0. it means that x>0, and again (y+z)<0, and x>0 so sufficient

very interested in oa

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by arora007 » Wed Sep 22, 2010 2:47 am
OA is D indeed!!
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