Tickets

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gmat009: Master | Next Rank: 500 Posts; Posts: 458; Joined: Sun Aug 31, 2008 10:44 amFollowed by: 1 member; Thanked: 3 times

by gmat009 » Mon Nov 17, 2008 10:26 am

A line of people waiting to enter a theater consists of 7 separate and successive groups. The first person in each group purchases one ticket for each person in the group and for no one else. If n is the total number of tickets sold for the first 6 groups, is n an even group?
(1) there are no more than 4 people in each group
(2) the 19th person in line purchases the tickets for the 7th group

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Source: Beat The GMAT — Data Sufficiency | Mon Nov 17, 2008 10:26 am

mals24: Legendary Member; Posts: 683; Joined: Tue Jul 22, 2008 1:58 pmFollowed by: 2 members; Location: Dubai; Thanked: 73 times

by mals24 » Mon Nov 17, 2008 11:07 am

IMO B

n is the total number of tickets sold to the first 6 groups.

St 1: There are no more than 4 people in a group
If there are equal number of people in each group then n will be even.

If the number is not equal, n could be odd or even.

3+4+2+3++3+4 = 19
Hence st 1 is INSUFF.

St 2 the 19th person purchases tickets for the 7th group. Since the first person of each group purchases tickets for each group, this statement means there were a total of 18 people standing before him in the line.
Hence n is even.
St2 is SUFF

Answer should be B

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4meonly: Legendary Member; Posts: 891; Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member; Thanked: 27 times; GMAT Score:660(

by 4meonly » Thu Nov 20, 2008 6:37 am

If n is the total number of tickets ........ is n an even group?

What the hell is this?

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