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Source: — Data Sufficiency |
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by fskilnik@GMATH » Tue Oct 12, 2010 11:43 am
Answer: E

(1) BIFURCATES:

> Take x = 20 and y = 0 , then (x +|y|)/2 = 10

> Take x = 21 and y = -1 , then (x +|y|)/2 = 11


(2) BIFURCATES, from exactly the same examples (for instance),

Therefore (1+2) also BIFURCATES, hence the answer is "E", as mentioned.

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by selango » Tue Oct 12, 2010 11:58 am
(x+|y|)/2=?

stmt1,

x+y=20

x=10,y=10,Average=10

x=30,y=-10,Average=20

Insuff

stmt2,

|x+y|=20

Either x+y=20 or x+y=-20

There are many values possible for X and Y and average varies.

Insuff

Combining 1 and 2,

x+y=20

x=10,y=10,Average=10

x=30,y=-10,Average=20

Insuff


Pick E
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by rb90 » Tue Oct 12, 2010 12:42 pm
Can we take average of x+|y| as x+y/2 ,or x-y/2,
then,
the first stmnt says x+y=20, but no way to find out x-y.Hence, insufficient

2nd stmnt, x+y=20 , or x+y= -20. So insufficient.

Combining the 2 stmnts, we get x+y=20. We still dont know x-y. So both together also insufficient.
Hence, the answer is E.
I just wanted to confirm if this working is correct, or just coincidence that i got it right.
Thanks for such immediate replies! :)
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