(r,s)

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(r,s)

by dreamv » Wed Feb 22, 2012 2:28 pm
In the xy-plane, does the line with equation y=3x+2 contain the point (r,s)?

1) (3r+2-s)(4r+9-s)=0
2) (4r-6-s)(3r+2-s)=0
Source: — Data Sufficiency |

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by pemdas » Wed Feb 22, 2012 4:10 pm
dreamv wrote:In the xy-plane, does the line with equation y=3x+2 contain the point (r,s)?

1) (3r+2-s)(4r+9-s)=0
2) (4r-6-s)(3r+2-s)=0
x=r and y=s, then question rephrased looks such as - 'does s=3r+2?'
st(1) either 3r+2-s=0 or 4r+9-s=0. Both lead to s=3r+2 or s=4r+9. So, if s=4r+9, the first condition, i.e. s=3r+2 is not effected. Not Sufficient
st(2) the same logic here, either s=4r+6 or s=3r+2 Not Sufficient
Combining st(1&2): Since 4r+9 is not equal to 4r+6, or 9=!6 we conclude s=3r+2 is the only option possible, Sufficient

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by Anurag@Gurome » Wed Feb 22, 2012 7:44 pm
dreamv wrote:In the xy-plane, does the line with equation y=3x+2 contain the point (r,s)?

1) (3r+2-s)(4r+9-s)=0
2) (4r-6-s)(3r+2-s)=0

If the line y = 3x + 2 has to contain the point (r, s), then s = 3r + 2.

(1) (3r + 2 - s)(4r + 9 - s) = 0 implies 3r + 2 - s = 0 or 4r + 9 - s = 0.
No definite answer; NOT sufficient.

(2) (4r - 6 - s)(3r + 2 - s) = 0 implies 3r + 2 - s = 0 or 4r - 6 - s = 0.
No definite answer; NOT sufficient.

Combining (1) and (2), s = 3r + 2
So, both statements together are sufficient to answer the question.

The correct answer is C.
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