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by bburton11 » Thu Jun 18, 2009 8:42 am
Pat, Kate, and Mark charged a total of 162 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate.

90 Hours
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by scoobydooby » Thu Jun 18, 2009 8:56 am
let Kate charge x hrs, then Pat charges 2x hrs.
Pat charges 1/3 of what Mark charges=>2x=1/3M=>M=6x

so x+2x+6x=162=> x=18 hrs

Mark charges 6x, and Kate x, so Mark charges 6x-x=5x hrs more=> 5*18=90 hrs more
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