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by naaga » Sat Feb 14, 2009 12:23 pm
For integers a, b, and c, a/(b-c)=1 , What is the value of (b-c)/b
(1) a/b=3/5
(2) a and b have no common factors greater than 1.


folks plz help me out...give explanation

thanks in advance
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by cramya » Sat Feb 14, 2009 1:00 pm
I would go wiht A

Given:
a/(b-c)=1
a= b-c
c = b-a

To find b-c/b = 1 - c/b = 1- (b-a)/b

Stmt I

Given a/b = 3/5

Possible to obtain a in term of b and hence the value 1- (b-a)/b can be found

SUFF

Stmt II

Few different values that fit the bill
a=2 b=15
a=2 b=11

INSUFF (since we get different values for 1- (b-a)/b)

Choose A
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by naaga » Sat Feb 14, 2009 1:06 pm
OA - (A)
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